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18+14x-x^2=0
We add all the numbers together, and all the variables
-1x^2+14x+18=0
a = -1; b = 14; c = +18;
Δ = b2-4ac
Δ = 142-4·(-1)·18
Δ = 268
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{268}=\sqrt{4*67}=\sqrt{4}*\sqrt{67}=2\sqrt{67}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{67}}{2*-1}=\frac{-14-2\sqrt{67}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{67}}{2*-1}=\frac{-14+2\sqrt{67}}{-2} $
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